7.19
Consider a Schottky diode built on n
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-type Silicon, as sketched in the figure. The Schottky metal is Al that has a Schottky barrier height on n
-type Si of
qφBn=0.68eV.The doping level in the
nregion is
ND=cm-3.In order to provide a good ohmic contact to this diode, there is an
n+region with a doping level of
ND+=cm-3. Alis also used as the ohmic metal.
Consider this structure in thermal equilibrium at room temperature. Use Boltzmann statistics to treat the
n+region.
(
a
)Sketch a complete energy band diagram across the entire structure
(from metal to metal
).Indicate the location of the Fermi level. Assume that both semiconductor regions are wide enough to fully accommodate the depletion regions associated with the metal
-semiconductor junctions. Be neat in your sketch.
(
b
)Compute the built
-in potential of the metal
-semiconductor junction on the left.
(
c
)Compute the built
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-in potential of the
n-n+junction.
(
d
)Compute the built
-in potential of the metal
-semiconductor junction on the right.
(
e
)Is there a voltage difference across the terminals of this device?
shawntedwards:
the numbering of the screw attach tabs dont match what I show on the diode I have
Its not obvious where the alternative numbering comes from, but the datasheet representation is generally correct. In any case, the diode test function available on most multimeters should let a person remove doubt in a few seconds.
shawntedwards:shawntedwards:
I will also have the diode mounted on a 15w heatsink.
That would seem reasonable, considering that the diode could be expected to burn on the order of 12W under the stated maximum conditions. It should be understood however, that heat sink ratings are (necessarily) based on a lot of stated or implied assumptions that may or may not align with ones particular circumstances. This post may offer insights on the topic.
shawntedwards:shawntedwards:
My installation should see around 20amps max, probably around 10amps continuous.
Thatd be light work for one of the diodes in the package individually, so the question of whether or not two in parallel would share equitably seems irrelevant in this case.
It may be of benefit to zoom out a bit and consider the context of how & why youre thinking of using the device in the first place. After all, it doesnt really matter how well one carries out the details if the overall plan is ill-fated
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